Integrand size = 23, antiderivative size = 267 \[ \int \frac {\sin ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\frac {\left (5 a^3+60 a^2 b+120 a b^2+64 b^3\right ) x}{16 a^5}-\frac {\sqrt {b} (a+b)^{3/2} (3 a+8 b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{2 a^5 f}-\frac {\left (33 a^2+82 a b+48 b^2\right ) \cos (e+f x) \sin (e+f x)}{48 a^3 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {(9 a+8 b) \cos ^3(e+f x) \sin (e+f x)}{24 a^2 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {\cos ^3(e+f x) \sin ^3(e+f x)}{6 a f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {b \left (19 a^2+52 a b+32 b^2\right ) \tan (e+f x)}{16 a^4 f \left (a+b+b \tan ^2(e+f x)\right )} \]
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Time = 0.53 (sec) , antiderivative size = 267, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.304, Rules used = {4217, 481, 592, 541, 536, 209, 211} \[ \int \frac {\sin ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=-\frac {\sqrt {b} (a+b)^{3/2} (3 a+8 b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{2 a^5 f}+\frac {(9 a+8 b) \sin (e+f x) \cos ^3(e+f x)}{24 a^2 f \left (a+b \tan ^2(e+f x)+b\right )}-\frac {b \left (19 a^2+52 a b+32 b^2\right ) \tan (e+f x)}{16 a^4 f \left (a+b \tan ^2(e+f x)+b\right )}-\frac {\left (33 a^2+82 a b+48 b^2\right ) \sin (e+f x) \cos (e+f x)}{48 a^3 f \left (a+b \tan ^2(e+f x)+b\right )}+\frac {x \left (5 a^3+60 a^2 b+120 a b^2+64 b^3\right )}{16 a^5}+\frac {\sin ^3(e+f x) \cos ^3(e+f x)}{6 a f \left (a+b \tan ^2(e+f x)+b\right )} \]
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Rule 209
Rule 211
Rule 481
Rule 536
Rule 541
Rule 592
Rule 4217
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x^6}{\left (1+x^2\right )^4 \left (a+b+b x^2\right )^2} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\cos ^3(e+f x) \sin ^3(e+f x)}{6 a f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {\text {Subst}\left (\int \frac {x^2 \left (3 (a+b)+(b-6 (a+b)) x^2\right )}{\left (1+x^2\right )^3 \left (a+b+b x^2\right )^2} \, dx,x,\tan (e+f x)\right )}{6 a f} \\ & = \frac {(9 a+8 b) \cos ^3(e+f x) \sin (e+f x)}{24 a^2 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {\cos ^3(e+f x) \sin ^3(e+f x)}{6 a f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {\text {Subst}\left (\int \frac {(a+b) (9 a+8 b)+\left (-24 a^2-65 a b-40 b^2\right ) x^2}{\left (1+x^2\right )^2 \left (a+b+b x^2\right )^2} \, dx,x,\tan (e+f x)\right )}{24 a^2 f} \\ & = -\frac {\left (33 a^2+82 a b+48 b^2\right ) \cos (e+f x) \sin (e+f x)}{48 a^3 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {(9 a+8 b) \cos ^3(e+f x) \sin (e+f x)}{24 a^2 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {\cos ^3(e+f x) \sin ^3(e+f x)}{6 a f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {\text {Subst}\left (\int \frac {3 (a+b) \left (5 a^2+22 a b+16 b^2\right )-3 b \left (33 a^2+82 a b+48 b^2\right ) x^2}{\left (1+x^2\right ) \left (a+b+b x^2\right )^2} \, dx,x,\tan (e+f x)\right )}{48 a^3 f} \\ & = -\frac {\left (33 a^2+82 a b+48 b^2\right ) \cos (e+f x) \sin (e+f x)}{48 a^3 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {(9 a+8 b) \cos ^3(e+f x) \sin (e+f x)}{24 a^2 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {\cos ^3(e+f x) \sin ^3(e+f x)}{6 a f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {b \left (19 a^2+52 a b+32 b^2\right ) \tan (e+f x)}{16 a^4 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {\text {Subst}\left (\int \frac {6 (a+b)^2 \left (5 a^2+36 a b+32 b^2\right )-6 b (a+b) \left (19 a^2+52 a b+32 b^2\right ) x^2}{\left (1+x^2\right ) \left (a+b+b x^2\right )} \, dx,x,\tan (e+f x)\right )}{96 a^4 (a+b) f} \\ & = -\frac {\left (33 a^2+82 a b+48 b^2\right ) \cos (e+f x) \sin (e+f x)}{48 a^3 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {(9 a+8 b) \cos ^3(e+f x) \sin (e+f x)}{24 a^2 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {\cos ^3(e+f x) \sin ^3(e+f x)}{6 a f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {b \left (19 a^2+52 a b+32 b^2\right ) \tan (e+f x)}{16 a^4 f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {\left (b (a+b)^2 (3 a+8 b)\right ) \text {Subst}\left (\int \frac {1}{a+b+b x^2} \, dx,x,\tan (e+f x)\right )}{2 a^5 f}+\frac {\left (5 a^3+60 a^2 b+120 a b^2+64 b^3\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\tan (e+f x)\right )}{16 a^5 f} \\ & = \frac {\left (5 a^3+60 a^2 b+120 a b^2+64 b^3\right ) x}{16 a^5}-\frac {\sqrt {b} (a+b)^{3/2} (3 a+8 b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{2 a^5 f}-\frac {\left (33 a^2+82 a b+48 b^2\right ) \cos (e+f x) \sin (e+f x)}{48 a^3 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {(9 a+8 b) \cos ^3(e+f x) \sin (e+f x)}{24 a^2 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {\cos ^3(e+f x) \sin ^3(e+f x)}{6 a f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {b \left (19 a^2+52 a b+32 b^2\right ) \tan (e+f x)}{16 a^4 f \left (a+b+b \tan ^2(e+f x)\right )} \\ \end{align*}
Result contains complex when optimal does not.
Time = 19.91 (sec) , antiderivative size = 2468, normalized size of antiderivative = 9.24 \[ \int \frac {\sin ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\text {Result too large to show} \]
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Time = 5.73 (sec) , antiderivative size = 204, normalized size of antiderivative = 0.76
method | result | size |
derivativedivides | \(\frac {-\frac {\left (a +b \right )^{2} b \left (\frac {a \tan \left (f x +e \right )}{2 a +2 b +2 b \tan \left (f x +e \right )^{2}}+\frac {\left (3 a +8 b \right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {\left (a +b \right ) b}}\right )}{2 \sqrt {\left (a +b \right ) b}}\right )}{a^{5}}+\frac {\frac {\left (-\frac {9}{4} a^{2} b -\frac {3}{2} a \,b^{2}-\frac {11}{16} a^{3}\right ) \tan \left (f x +e \right )^{5}+\left (-4 a^{2} b -3 a \,b^{2}-\frac {5}{6} a^{3}\right ) \tan \left (f x +e \right )^{3}+\left (-\frac {5}{16} a^{3}-\frac {7}{4} a^{2} b -\frac {3}{2} a \,b^{2}\right ) \tan \left (f x +e \right )}{\left (1+\tan \left (f x +e \right )^{2}\right )^{3}}+\frac {\left (5 a^{3}+60 a^{2} b +120 a \,b^{2}+64 b^{3}\right ) \arctan \left (\tan \left (f x +e \right )\right )}{16}}{a^{5}}}{f}\) | \(204\) |
default | \(\frac {-\frac {\left (a +b \right )^{2} b \left (\frac {a \tan \left (f x +e \right )}{2 a +2 b +2 b \tan \left (f x +e \right )^{2}}+\frac {\left (3 a +8 b \right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {\left (a +b \right ) b}}\right )}{2 \sqrt {\left (a +b \right ) b}}\right )}{a^{5}}+\frac {\frac {\left (-\frac {9}{4} a^{2} b -\frac {3}{2} a \,b^{2}-\frac {11}{16} a^{3}\right ) \tan \left (f x +e \right )^{5}+\left (-4 a^{2} b -3 a \,b^{2}-\frac {5}{6} a^{3}\right ) \tan \left (f x +e \right )^{3}+\left (-\frac {5}{16} a^{3}-\frac {7}{4} a^{2} b -\frac {3}{2} a \,b^{2}\right ) \tan \left (f x +e \right )}{\left (1+\tan \left (f x +e \right )^{2}\right )^{3}}+\frac {\left (5 a^{3}+60 a^{2} b +120 a \,b^{2}+64 b^{3}\right ) \arctan \left (\tan \left (f x +e \right )\right )}{16}}{a^{5}}}{f}\) | \(204\) |
risch | \(\frac {5 x}{16 a^{2}}+\frac {15 x b}{4 a^{3}}+\frac {15 x \,b^{2}}{2 a^{4}}+\frac {4 x \,b^{3}}{a^{5}}-\frac {3 i {\mathrm e}^{4 i \left (f x +e \right )}}{128 a^{2} f}-\frac {i {\mathrm e}^{-2 i \left (f x +e \right )} b}{2 a^{3} f}-\frac {15 i {\mathrm e}^{-2 i \left (f x +e \right )}}{128 a^{2} f}+\frac {3 i {\mathrm e}^{-4 i \left (f x +e \right )}}{128 a^{2} f}+\frac {i {\mathrm e}^{-4 i \left (f x +e \right )} b}{32 a^{3} f}+\frac {3 i {\mathrm e}^{2 i \left (f x +e \right )} b^{2}}{8 a^{4} f}+\frac {i {\mathrm e}^{2 i \left (f x +e \right )} b}{2 a^{3} f}+\frac {15 i {\mathrm e}^{2 i \left (f x +e \right )}}{128 a^{2} f}-\frac {3 i {\mathrm e}^{-2 i \left (f x +e \right )} b^{2}}{8 a^{4} f}-\frac {i b \left (a^{3} {\mathrm e}^{2 i \left (f x +e \right )}+4 a^{2} b \,{\mathrm e}^{2 i \left (f x +e \right )}+5 a \,b^{2} {\mathrm e}^{2 i \left (f x +e \right )}+2 b^{3} {\mathrm e}^{2 i \left (f x +e \right )}+a^{3}+2 a^{2} b +a \,b^{2}\right )}{a^{5} f \left (a \,{\mathrm e}^{4 i \left (f x +e \right )}+2 a \,{\mathrm e}^{2 i \left (f x +e \right )}+4 b \,{\mathrm e}^{2 i \left (f x +e \right )}+a \right )}-\frac {i {\mathrm e}^{4 i \left (f x +e \right )} b}{32 a^{3} f}-\frac {3 \sqrt {-a b -b^{2}}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-a b -b^{2}}-a -2 b}{a}\right )}{4 f \,a^{3}}-\frac {11 \sqrt {-a b -b^{2}}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-a b -b^{2}}-a -2 b}{a}\right ) b}{4 f \,a^{4}}-\frac {2 \sqrt {-a b -b^{2}}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-a b -b^{2}}-a -2 b}{a}\right ) b^{2}}{f \,a^{5}}+\frac {3 \sqrt {-a b -b^{2}}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-a b -b^{2}}+a +2 b}{a}\right )}{4 f \,a^{3}}+\frac {11 \sqrt {-a b -b^{2}}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-a b -b^{2}}+a +2 b}{a}\right ) b}{4 f \,a^{4}}+\frac {2 \sqrt {-a b -b^{2}}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-a b -b^{2}}+a +2 b}{a}\right ) b^{2}}{f \,a^{5}}-\frac {\sin \left (6 f x +6 e \right )}{192 a^{2} f}\) | \(708\) |
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Time = 0.33 (sec) , antiderivative size = 674, normalized size of antiderivative = 2.52 \[ \int \frac {\sin ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\left [\frac {3 \, {\left (5 \, a^{4} + 60 \, a^{3} b + 120 \, a^{2} b^{2} + 64 \, a b^{3}\right )} f x \cos \left (f x + e\right )^{2} + 3 \, {\left (5 \, a^{3} b + 60 \, a^{2} b^{2} + 120 \, a b^{3} + 64 \, b^{4}\right )} f x + 6 \, {\left (3 \, a^{2} b + 11 \, a b^{2} + 8 \, b^{3} + {\left (3 \, a^{3} + 11 \, a^{2} b + 8 \, a b^{2}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt {-a b - b^{2}} \log \left (\frac {{\left (a^{2} + 8 \, a b + 8 \, b^{2}\right )} \cos \left (f x + e\right )^{4} - 2 \, {\left (3 \, a b + 4 \, b^{2}\right )} \cos \left (f x + e\right )^{2} + 4 \, {\left ({\left (a + 2 \, b\right )} \cos \left (f x + e\right )^{3} - b \cos \left (f x + e\right )\right )} \sqrt {-a b - b^{2}} \sin \left (f x + e\right ) + b^{2}}{a^{2} \cos \left (f x + e\right )^{4} + 2 \, a b \cos \left (f x + e\right )^{2} + b^{2}}\right ) - {\left (8 \, a^{4} \cos \left (f x + e\right )^{7} - 2 \, {\left (13 \, a^{4} + 8 \, a^{3} b\right )} \cos \left (f x + e\right )^{5} + {\left (33 \, a^{4} + 82 \, a^{3} b + 48 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{3} + 3 \, {\left (19 \, a^{3} b + 52 \, a^{2} b^{2} + 32 \, a b^{3}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{48 \, {\left (a^{6} f \cos \left (f x + e\right )^{2} + a^{5} b f\right )}}, \frac {3 \, {\left (5 \, a^{4} + 60 \, a^{3} b + 120 \, a^{2} b^{2} + 64 \, a b^{3}\right )} f x \cos \left (f x + e\right )^{2} + 3 \, {\left (5 \, a^{3} b + 60 \, a^{2} b^{2} + 120 \, a b^{3} + 64 \, b^{4}\right )} f x + 12 \, {\left (3 \, a^{2} b + 11 \, a b^{2} + 8 \, b^{3} + {\left (3 \, a^{3} + 11 \, a^{2} b + 8 \, a b^{2}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt {a b + b^{2}} \arctan \left (\frac {{\left (a + 2 \, b\right )} \cos \left (f x + e\right )^{2} - b}{2 \, \sqrt {a b + b^{2}} \cos \left (f x + e\right ) \sin \left (f x + e\right )}\right ) - {\left (8 \, a^{4} \cos \left (f x + e\right )^{7} - 2 \, {\left (13 \, a^{4} + 8 \, a^{3} b\right )} \cos \left (f x + e\right )^{5} + {\left (33 \, a^{4} + 82 \, a^{3} b + 48 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{3} + 3 \, {\left (19 \, a^{3} b + 52 \, a^{2} b^{2} + 32 \, a b^{3}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{48 \, {\left (a^{6} f \cos \left (f x + e\right )^{2} + a^{5} b f\right )}}\right ] \]
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Timed out. \[ \int \frac {\sin ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\text {Timed out} \]
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Time = 0.27 (sec) , antiderivative size = 302, normalized size of antiderivative = 1.13 \[ \int \frac {\sin ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=-\frac {\frac {3 \, {\left (19 \, a^{2} b + 52 \, a b^{2} + 32 \, b^{3}\right )} \tan \left (f x + e\right )^{7} + {\left (33 \, a^{3} + 253 \, a^{2} b + 516 \, a b^{2} + 288 \, b^{3}\right )} \tan \left (f x + e\right )^{5} + {\left (40 \, a^{3} + 319 \, a^{2} b + 564 \, a b^{2} + 288 \, b^{3}\right )} \tan \left (f x + e\right )^{3} + 3 \, {\left (5 \, a^{3} + 41 \, a^{2} b + 68 \, a b^{2} + 32 \, b^{3}\right )} \tan \left (f x + e\right )}{a^{4} b \tan \left (f x + e\right )^{8} + {\left (a^{5} + 4 \, a^{4} b\right )} \tan \left (f x + e\right )^{6} + a^{5} + a^{4} b + 3 \, {\left (a^{5} + 2 \, a^{4} b\right )} \tan \left (f x + e\right )^{4} + {\left (3 \, a^{5} + 4 \, a^{4} b\right )} \tan \left (f x + e\right )^{2}} - \frac {3 \, {\left (5 \, a^{3} + 60 \, a^{2} b + 120 \, a b^{2} + 64 \, b^{3}\right )} {\left (f x + e\right )}}{a^{5}} + \frac {24 \, {\left (3 \, a^{3} b + 14 \, a^{2} b^{2} + 19 \, a b^{3} + 8 \, b^{4}\right )} \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {{\left (a + b\right )} b}}\right )}{\sqrt {{\left (a + b\right )} b} a^{5}}}{48 \, f} \]
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Time = 0.36 (sec) , antiderivative size = 294, normalized size of antiderivative = 1.10 \[ \int \frac {\sin ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\frac {\frac {3 \, {\left (5 \, a^{3} + 60 \, a^{2} b + 120 \, a b^{2} + 64 \, b^{3}\right )} {\left (f x + e\right )}}{a^{5}} - \frac {24 \, {\left (3 \, a^{3} b + 14 \, a^{2} b^{2} + 19 \, a b^{3} + 8 \, b^{4}\right )} {\left (\pi \left \lfloor \frac {f x + e}{\pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (b\right ) + \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {a b + b^{2}}}\right )\right )}}{\sqrt {a b + b^{2}} a^{5}} - \frac {24 \, {\left (a^{2} b \tan \left (f x + e\right ) + 2 \, a b^{2} \tan \left (f x + e\right ) + b^{3} \tan \left (f x + e\right )\right )}}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )} a^{4}} - \frac {33 \, a^{2} \tan \left (f x + e\right )^{5} + 108 \, a b \tan \left (f x + e\right )^{5} + 72 \, b^{2} \tan \left (f x + e\right )^{5} + 40 \, a^{2} \tan \left (f x + e\right )^{3} + 192 \, a b \tan \left (f x + e\right )^{3} + 144 \, b^{2} \tan \left (f x + e\right )^{3} + 15 \, a^{2} \tan \left (f x + e\right ) + 84 \, a b \tan \left (f x + e\right ) + 72 \, b^{2} \tan \left (f x + e\right )}{{\left (\tan \left (f x + e\right )^{2} + 1\right )}^{3} a^{4}}}{48 \, f} \]
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Time = 20.40 (sec) , antiderivative size = 1461, normalized size of antiderivative = 5.47 \[ \int \frac {\sin ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\text {Too large to display} \]
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